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GET OUT YOUR CALCULATORS!
by Bill Graham
Calculator discourseWhat do you think about students using calculators in school? Most people have strong opinions on this issue. I believe that calculators are a great tool to open up problem-solving vistas once basic arithmetic skills (multiplication tables, etc.) have been mastered.Sad to say, some students don’t seem capable of mastering these basic skills. When they get to seventh or eighth grade, they are still incapable or unmotivated to memorize 6 × 9 = 54. Then, I hand them a calculator and let them learn other areas of mathematics in spite of their shortcoming. That’s my opinion. What’s yours?
First calculator puzzleHere is your first calculator puzzle. Enter the number 12,345,679 on your calculator. Now multiply it by 45. What is the result? All fives I hope. Suppose your favorite number is eight. Multiply the original 12,345, 679 by 72 and you should have all eights. What’s the rule to determine what to multiply by if you want all threes or all sevens? Do you see why this works?
Remainder discourse
You would not get a remainder if the original number is a multiple of five (a number than ends in five or zero) but would get a remainder for all other numbers. So, you would expect a remainder 80 percent of the time. If you divided by seven, you would expect a whole number for an answer every multiple of seven, or in other words, you would expect a remainder about six-sevenths of the time.
Another puzzleNow here’s the puzzle. I have known it for years and it’s one of my favorites. Choose any random three-digit number. For example, let’s use 347. Enter it twice on your calculator making the six-digit number 347,347. If you divide it by seven, wouldn’t you expect a remainder six-sevenths of the time? So try it. The answer is 49,621 with no remainder.Just lucky I guess. OK, let’s keep going. Now divide the answer on your calculator by 11. Surely we’ll get a remainder this time. Nope, exactly 4,511. Finally, divide that answer by 13 and check for a remainder. Whoa! Not only is there no remainder again, but the answer is the three digit number you started with, namely 347. If you try this same procedure starting with any other repeated three-digit number, the answers will always be whole numbers, and the final quotient will always be the number you started with. How come? |
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Contents copyright 2005 by Bill Graham and ParaComp, Inc.
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